Question

the number of Gram molecules of oxygen in 6.02 ×10^24 CO molecules is

Answer 1

1 mole CO equivalent to 6.02x10^23molecules of CO contain 6.02x10^23atoms of Oxygen. So 6.02x10^24 CO molecules contain 6.02x10^24 atoms of O which is equivalent to 10 gm-atoms of oxygen. Since Oxygen is diatomic, 10 g-atom = 1/2x10 g-molecule of Oxygen = 5 gram-molecule of O2 = 5 grams of O2