Question

the number of gram molecules of Oxygen in 6.02 ×10^24CO molecules is

Answer 1

1 mole CO equivalent to 6.02x10^23 molecules of CO contain 6.02x10^23 atoms of Oxygen. So 6.02x10^24 CO molecules contain 6.02x10^24 atoms of O which is equivalent to 10 gm-atoms of oxygen. Since Oxygen is diatomic, 10 g-atom = 1/2x10 g-molecule of Oxygen = 5 gram-molecule of O2 = 5 grams of O2 molecule.