Question

The number of gram molecules of oxygen in 6.02 × 10²⁴
CO molecules is
(a) 10 gm molecules (b) 5 gm molecules
(c) 1 gm molecules (d) 0.5 gm molelcules

Answer 1

The number of gram molecules of oxygen in 6.02 × 10²⁴  CO molecules = 5 gm molecules

Explanation:

One mole of any substance contain Avogadro number of molecules.

• $Number\,of\,moles=\frac{Number\,of\,molecules}{Avogadro\,number}$
• $Avogadro\,number=6.02\times 10^{23}$
• $\therefore Number \, of \, moles =\frac{6.02\times10^{24}}{6.02\times10^{23}}=10$
• 10 moles of $CO$ molecules contain 10 g of oxygen atoms
• Therefore 10 moles of $CO$ molecules or $6.02 \times 10^{24}$ $CO$ molecules containing oxygen molecules = 5 g molecules
• Therefore, The correct answer is option (b)