Question

The number of gram molecules of oxygen in 6.02×1024 co molecule is

Answer 1

1 mole CO equivalent to 6.02x10^23molecules of CO contain 6.02x10^23atoms of Oxygen. So 6.02x10^24 CO molecules contain 6.02x10^24 atoms of O which is equivalent to 10 gm-atoms of oxygen. Since Oxygen is diatomic, 10 g-atom = 1/2x10 g-molecule of Oxygen = 5 gram-molecule of O2 = 5 grams of O2 molecule.
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Answer 2

Answer:

The number of gram molecules of oxygen in $6.02\times 10^{24}$ CO molecule is 5.

Explanation:

Number of molecules of CO = $6.02\times 10^{24}$

Number of oxygen atoms:

$1\times 6.02\times 10^{24}=6.02\times 10^{24}$ atoms

1 oxygen  molecule is composed of 2 oxygen atoms.So, number of oxygen molecules:

$\frac{6.02\times 10^{24}}{2}=3.01\times 10^{24}$

Moles of oxygen gas:

$\frac{3.01\times 10^{24}}{6.02\times 10^{23}}=5 mol$

1 mole = 1 gram molecule of compound

5 mole = 5 gram molecules of oxygen

The number of gram molecules of oxygen in $6.02\times 10^{24}$ CO molecule is 5.