Question

The number of H+ ions produced by complete ionization of 9.8g of H3PO4 is: ??

Answer 1

Answer:

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Explanation:

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Answer 2

The number of H⁺ ions produced by complete ionisation of 9.8 g of H₃PO₄ is...

solution : here mass of H₃PO₄ = 9.8 g

molar mass of H₃PO₄ = 98 g/mol

so no of moles of H₃PO₄ = 9.8/98 = 0.1

On complete ionisation of phosphoric acid (H₃PO₄),

H₃PO₄ ⇔ 3H⁺ + PO₄³¯

here we see, three H⁺ ions are produced by complete ionisation of 1 molecule of H₃PO₄.

∴ 0.3 mol of H⁺ ions is produced by complete ionisation of 0.1 mol of H₃PO₄.

now number of H⁺ ions = no of moles × Avogadro's number

= 0.3 × 6.023 × 10²³

= 1.8069 × 10²³

Therefore the number of H⁺ ions would be 1.8069 × 10²³