Question

the number of h + ions produced by the complete ionization of 9.8 g h 3 PO 4 is​

Answer 1

Explanation:

The molar mass of H2SO4 is 98.1 (rounded to three SFs), so 9.8 g would equate to 0.0999 mols of H2SO4 (again rounded to three SFs).

We can then multiply 0.0999 mols by Avogadro’s number (6.02 x 10^23) to find that there are roughly 6.02 x 10^22 molecules of H2SO4 in 9.8g of the compound.

But, because H2SO4 is a diprotic acid, therefore we need to multiply the quantity of H2SO4 molecules in 9.8g by 2. Hence, in 9.8g of H2SO4, there are roughly 1.2 x 10^23 H+ ions.