Question

the number of incorrect answers on a true-false competency test of 15 students were recorded as fellows:
2,1,3,0,1,3,6,0,3,3,5,2,1,4 and 2.Make a simple frequency distribution with unit class and find:
i: the mean
ii: the median
iii: the mode​

Answer 1

Answer:

Mean = Sum of the observations / number of observation=( 2 1 3 0 1 3 6 0 3 3 5 2 1 4 2) / 15= 36 /15= 2.4 first we arrange the data in ascending order0,0,1,1,1,2,2, 2 ,3,3,3,3,4,5,6Median = [ ( n 1 ) / 2 ]

Answer 2

Answer:

(i) mean = 1.73

(ii)  median = 2

(iii)  mode for the given data set = 3

Step-by-step explanation:

arrange the data in a frequency table:

x      f        c.f        fx

0      2        2        0

1       3        5        3

2      3        8        6

3       4       12       12

4        1        13       4

5        1       14        5

6        1        15       6

total 15 observations

(i) sample mean = $\frac{f1x1+f2x2+f3x3+....+fnxn}{n}$

= ∑fiXi/∑fi

= $\frac{0+3+6+12+4+5+6}{15}$

 =$\frac{26}{15}$ = 1.73

(ii) n = 15

$\frac{n}{2}$ = $\frac{15}{2}$ = 7.5

cumulative frequency, cf, just greater than 7.5 is 8

value of x corresponding to 8 is 2

median = 2

(iii) mode is the value that appear the most in the data set

    for the given data set 3 appears four times

         mode for the given data set = 3