Math, asked by JDaniel, 8 months ago

The number of integer values of 'x' satisfying x^2 - 4x + 2 / x^2 - x - 30 Less than or Equal to 0 is​

Answers

Answered by amitnrw
1

Given :   (x²- 4x + 2) / (x² - x - 30)  ≤  0  

To Find : The number of integer values of 'x'

Solution:

(x² - 4x + 2) / (x² - x - 30)  ≤  0  

Case 1 :

x² - 4x + 2 = 0    and  x² - x - 30 ≠ 0

=> no integral value of x    ,   (x - 6)(x + 5) = 0  => x  ≠ 6 , - 5

Case 2 :

x² - 4x + 2  >  0     and    x² - x - 30 <  0

(x - 2)² -  2  > 0                  (x - 6)(x + 5)  <  0

(x - 2)² > 2                          - 5 < x  <   6

=>  x - 2 >  √2

=> x >  2 + √2

=> x ≥ 4   for integral values

or x  - 2  < - √2

=> x < 2 - √2

=> x  ≤ 0     for integral values

x ≥ 4    ,    x  ≤ 0

 - 5 < x  <   6

- 4 , - 3 , - 2 , - 1 ,  0  ,   4 , 5    

Case 3 :

x² - 4x + 2  < 0     and     x² - x - 30 >  0

(x - 2)² -  2  <  0                  (x - 6)(x + 5)  >  0

(x - 2)²  <  2                           x < - 5  and  x  >  6

=> -√2  <  x - 2  <  √2

=>   2 - √2 < x  < 2 + √2

1  ≤  x  ≤  3 for integral values

 x < - 5  and  x  >  6

no common solution

- 4 , - 3 , - 2 , - 1 ,  0  ,   4 , 5    

Hence 7 integral values of 'x'

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