Question

the number of integers from 1 to 1000 in which at least two consecutive digits are equal is​

Answer 1

Answer:

180 ( without considering 1000)

181 ( considering 1000)

Step-by-step explanation:

11 , 22 , 33 , 44 , 55 , 66 , 77 , 88 , 99 = 9 numbers

100 , 111 , 122 , 133 , 144 , 155 , 166 , 177 , 188 , 199  

till 999  = 10 * 9 = 90 numbers

110 , 112 , 113 , 114 , 115 , 116 , 117 , 118 , 199

220 , 221 , 223 , 224 , 225 , 226 , 227 , 228 , 229

till 999    

so 9 * 9 = 81 numbers

9 + 90 + 81 = 180 numbers

if 1000 is also considered then 181 Numbers

Answer 2

Step-by-step explanation:

amit has given the right answer