the number of integers N between 100 and 1000 such that the sum of the digits in N is 10 is
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Answer is 100
You can solve this sum logically or by permutation and combination
logically ,
between 100 and 101 there will only one possibility and same way for all others
thus,
b/w 100 and 200 there will 10 possibility
Therefore ,
10×10=100
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