The number of integers satisfying (x-1)(x-5)
(x-8)(x-11) < 0 are -
(A) 3
(B) 5
(C) 4
(D) infinite
0 (A)
(B
0 (0)
© (D)
Answers
Answered by
0
Answer:
option A and C both ared correct
Answered by
2
Answer:
Option B
Step-by-step explanation:
Either 1 or 3 of these terms have to be negative for the final product to be negative.
How can one term be negative?
If x is smaller than the largest term but greater then the rest of the terms, the final term will be negative but the rest will be positive. All values of x between 8 and 11 will satisfy the conditions. Thus x can be 9 or 10.
How can three terms be negative?
If x is larger than the first term but smaller than the rest, 3 terms will be negative. All values of x between 1 and 5 will satisfy the conditions. Thus x can be 2, 3 or 4.
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