Math, asked by suruj7861, 1 year ago

the number of integral value of 'm' is less than 50, so that the roots of the quadratic equation mx2+(2m-1)x+(m-2)=0 are rational,are. A) 6. B)7. C)8. D)none of these​

Answers

Answered by aquialaska
3

Answer:

Option A is correct.

Step-by-step explanation:

Given Quadratic Equation:

mx² + (2m+1)x + (m-2) = 0

To find: Number of value of m for which roots are  rational and m < 50.

We know the roots are rational if the Value of the discriminant is a perfect square number.

D = b² - 4ac

   = (2m-1)² - 4(m)(m-2)

   = 4m² + 1 - 4m - 4m² + 8m

   = 4m + 1

For the roots to be rational 4m + 1 should be a perfect square.

4m + 1 to be perfect square value of m = 2 , 6 , 12 , 20 , 30 and 42

Therefore, Option A is correct.

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