Chemistry, asked by tanubhavna7921, 1 year ago

The number of ions formed when [Cu(NH₃)₄SO₄] is dissolved in water is: a) 1 b) 2 c) 4 d) Zero

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Answered by Raghav1330
3

Answer: 2

Explanation: when dissolved, two ions comes as: -

We have a co ordination complex [Cu(NH3)4]2+ and (SO4)2-.This is a Cu2+, which will give dissipate four amine (NH3) ligands, to give rise to co ordination complex, [Cu(NH3)4]2+

But for case of neutral complex we need a certain dianion, as sulphate (SO4)2-, which goes in. When this will be dissolved in H2O i.e aqueous solution, the complex and sulphate ion will be enticed as separate entities. Hence 2 is the answer.

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