Question

the number of ions per mole of the complex CoCl3.5NH3 in aqueous solution will be?

Answer 1

Let CoCL3.NH3, n = 4, 5, 6
It is provided: '5'NH3(purple)
Therefore no of ios = 2

Answer 2

The number of ions per mole of the complex $CoCl_3.5NH_3$ in aqueous solution will be 3.

Explanation:

• As it is a coordination compound it can be written as $[Co(NH_3)_5Cl]Cl_2$.
• To get the aqueous solution of the given compound, the compound must be dissolved in the water.
• When it is dissolved in the water it leads to formation of 1 mole of cation and 2 mole of anion.
• The chemical equation involved in the reaction is as follows:

$\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2} \stackrel{\mathrm{H}_{2}O}{\longrightarrow}\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right]^{2+}+2 \mathrm{Cl}^{-}$

• Thus form the above equation it can be inferred that one mole of complex $CoCl_3.5NH_3$ in aqueous solution will be 3 ions (1 cation and 2 anion).

Learn more about such concept

Dissociation of sodium ferrocyanide

https://brainly.in/question/9362172

How to calculate van't hoff factor of coordination compounds?

https://brainly.in/question/3339485