Question

The number of ions present in 2L of a solution of 0.8 M K4[Fe(CN)6] is

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Answer 1

Hello Spoorthi

First calculate the number of moles by multiplying the volume and molarity it comes out to be 1.6

Now 1 mol gives 5 ions in water 1.6 mole will give 8 moles.

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Answer 2

The number of ions in the given amount of complex are $4.82\times 10^{24}$

Explanation:

To calculate the number of moles for given molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of complex = 0.8 M

Volume of solution = 2.00 L

Putting values in above equation, we get:

$0.8=\frac{\text{Moles of complex}}{2.00L}\\\\\text{Moles of complex}=(0.8\times 2)=1.6mol$

The chemical equation for the ionization of complex follows:

$K_4[Fe(CN)_6]\rightarrow 4K^++[Fe(CN)_6]^{4-}$

1 mole of complex produces in total of 5 ions

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, 1.6 moles of the complex will contain = $(5\times 1.6\times 6.022\times 10^{23})=4.82\times 10^{24}$ number of ions

Learn more about molarity and mole concept:

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