Question

The number of kj necessary to raise the temperature of 60.0 g of aluminum from 35°c to 55°c. Molar heat capacity of aluminum is 24j molâ’1kâ’1

Answer 1

 

Given :

Δ T = 55°C - 35°C

= > Δ T = 20°C

Number of moles = mass / molar mass

= > n = 60 g / 27 g/moles

= > n = 2.22 moles

Q = m C Δ T

= Q = 2.22 × 24 × 20

= Q = 1065.6

= Q = 1.0656

= Q = 1.066 kJ

ANSWER :

1.066 is the required answer !