Question

the number of line segment in abc is​

Answer 1

3 line segments if it is a triangle

Answer 2

Answer:

From geometry ∠AOF=B,∠AOE=C

Also, OF=bcosA.tan(90

0

−B)=bcosA.cotB=2RcosA.cosB

Similarly, OE=2RcosAcosC

In △OEF,cos(B+C)=

2.OE.OF

OE

2

+OF

2

−EF

2

⇒−cosA=

8R

2

cos

2

AcosBcosC

4R

2

cos

2

A(cos

2

B+cos

2

C)−EF

2

⇒EF

2

=4R

2

cos

2

A[cos

2

B+cos

2

C+2cosAcosBcosC]

=R

2

cos

2

Asin

2

A

( because in △ABC,cos

2

A+cos

2

B+cos

2

C=1−2cosAcosBcosC)

∴EF=Rsin2A=

2sinA

a

sin2A=acosA

Similarly, DF=bcosB