Question

The Number of linearly independent solutions of the system

2x + 3ky + (3k + 4)z = 0, x + (k + 4) + (4k +2)z = 0, x+2(k+1) + (3k + 4)z = 0

for k = 2 is…….​

Answer 1

here your answer, I hope you got it.