The number of lines passing through five points such that no three of them are collinear is
Answers
Answered by
2
Answer:
We know that a line consist minimum tow point, but five point are colinear
∴ total number of lines is 5×2=10
Answered by
0
Step-by-step explanation:
So the lines are AB, AC, AD, AE, BC, BD, BE, CD, CE, DE. So that makes 10 lines.
Similar questions