Question

The number of lines that can be drawn
through the point (5,2) at a distance 5 units
from the point (2,-2) is
​

Answer 1

Answer:

$\huge\bold\red{ANSWER}$

Step-by-step explanation:

→ $\large{\underline{\rm{\red{SOLUTION :}}}}$

⇒ let line through point (5,2) is with slope m

   y-2=mx-5m

   mx-y-5m+2=0

⇒ $5=[\frac{2m+2-5m+2}{\sqrt{m^2+1}}]$

⇒  $5 = [\frac{-3m + 4}{\sqrt{m^2+1}}]$

⇒  $25=\frac{(-3m+4)^2}{m^2+1}$

⇒  $25m^2+25=9m^2+16-24m$

⇒  $16m^2+9-24m=0$

⇒  $\boxed{(4m+3)^2}$ is your answer