Question

The number of local glucose molecules present in 10 ml of decimolar solution is

Answer 1

Answer:

6.0×10 race to 20

EXPLANATION:

Given, Molarity =0.1 M; V=10 ml=0.01 litre

Number of moles =Molarity×volume (in liters)

=0.1×0.01

=10 race to −3moles

Number of Molecules =moles×Avogadro number(NA)

=10 race to −3×6.0×10 race to 23

=6×10 race to 20 molecules