Question

The number of lone pair present in n-atom in nh4+ is-

Answer 1

Atomic number of NItrogen = 7 (1S2 2S2 2P3)

Number of valence electrons of Nitrogen = 5

In case of ammonia (NH3), three P electrons covalently bond with 3 hydrogen bonds while remaining two electrons do not participate in bonding or hybridization and exists as lone pair of electrons.

In case of NH4+, three P electrons covalently bond with 3 hydrogen bonds. H+ ion does not have any electron and a lone pair of electron is donated by nitrogen to H+ ion and forms covalent bond.

Thus, there is no lone pair of electrons on nitrogen in NH4+.

Answer 2

Answer :

0

Explanation:

Valence electrons = 5+4= 9

Due to +1  charge: 9-1=

8electrons

NH4+ contains 4 bonds ⇒ ie,8 electrons already used to make the bonds , hence no lone pair