Math, asked by syedabusufi8352, 9 months ago

the number of m1 values of n=4 is​

Answers

Answered by aliasif93429
1

Answer:

For nth orbital possible values of azimuthal quantum number, l are from 0 to (n−1). Total of n values.

In 4f orbital, n=4 and f-orbital has l=3

Magnetic quantum number ml have values from −l to +l and total of 2l+1 values. 

For l=3 total; values of ml are 7 and are:

For l=3,ml=−3−2,−1,0,1,2,3

Answered by shilpa85475
0
  • The magnetic quantum number specifies the orientation in space of an orbital of given energy and shape.
  • This number divides the subshell into individual orbitals which hold the electrons; there are (2L+1) orbitals in each subshell.
  • Thus, the s subshell has only one orbital, the p subshell has three orbitals, and so on.

For n=4, we have s, p, d, f subshells.

For s subshell, we have 2×0+1=1.

For p subshell, we have 2×1+1=3.

For d subshell, we have 2×2+1=5.

For f  subshell, we have 2×3+1=7.

  • The total value of m will be 1+3+5+7=16
  • The number og m1 values  of n=4 is 16
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