Question

The number of males females and children in a group are in the ratio of 4511. If the numbers of alles
females and chaires each is creased by 12. the new ratio becomes 6:79. What is the number of males in the
sroup after the increa
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Answer 1

Step-by-step explanation:

The Hardy-Weinberg law can be used under some circumstances to calculate genotype frequencies from allele frequences. Let A1 and A2 be two alleles at the same locus,

p is the frequency of allele A1 0 ≤ p ≤ 1

q is the frequency of allele A2 0 ≤ q ≤ 1 and p + q = 1

where the distribution of allele frequencies is the same in men and women, i.e.:

hommes (p,q) femmes (p,q)

if they procreate : (p + q)2 = p2 + 2pq + q2 = 1

where:

p2 = frequency of the A1 A1 genotype <-- HOMOZYGOTE

2pq = frequency of the A1 A2 genotype <-- HETEROZYGOTE

q2 = frequency of the A2 A2 genotyp <-- HOMOZYGOTE

these frequencies remain constant in successive generations.

Example : autosomal recessive inheritance with alleles A and a, and allele frequencies p and q:

--> frequency of the genotypes: : AA = p2 and the phenotypes [ ]: [A] = p2 + 2pq

Aa = 2pq [a] = q2

aa = q2

Example : phenylketonuria (recessive autosomal), of which the deleterious gene has a frequency of 1/100:

--> q = 1/100

therefore, the frequency of this disease is q2 = 1/10 000,

and the frequency of heterozygotes is 2pq = 2 x 99/100 x 1/100 = 2/100;

Note that there are a lot of heterozygotes: 1/50, two hundred times more than there are individuals suffering from the condition. .