Question

The number of millimoles of HCL require to neutralize 10 ml of 0.2 M Na2CO3 is
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Answer 1

Explanation:

Balanced equation:

2HCl(aq) + Na2CO3(aq) → 2NaCl(aq) + CO2(g) + H2O(l)

2mol HCl react with 1 mol Na2CO3

Mol Na2CO3 in 10mL of 0.2M solution = 10mL / 1000mL/L * 0.2 = 0.002 mol

0.002 mol = 0.002*1000 = 2 mmol Na2CO3

From the balanced equation ,

You require 2mmol *2 = 4mmol HCl for neutralisation.