Question

The number of mol of Ca2+ ion in 200 ml of 0.3 M of Ca3(PO4)2 is O 0.12 NA O 0.18 NA 0 2.4 NA O NA​

Answer 1

The number of mol of Ca2+ ion in 200 ml of 0.3 M of Ca3(PO4)2 is O 0.12 NA O 0.18 NA 0 2.4 NA O NA​ - 48071390.

Answer 2

$0.6$$\[{{N}_{A}}\]$ is the number of $\[C{{a}^{2+}}$ ion in 200 ml of 0.3M of $\[C{{a}_{3}}{{(P{{O}_{4}})}_{2}}$.

Explanation:

Volume of solution$=200ml=0.2l$

Molarity of the given solution$=0.3M$

Number of moles of $\[C{{a}_{3}}{{(P{{O}_{4}})}_{2}}$ $=x$

The equation is,

$\[C{{a}_{3}}{{(P{{O}_{4}})}_{2}}$ is Split into three $C{{a}^{2+}}$ and two $P{{O}_{4}}^{3-}$

$\[C{{a}_{3}}{{(P{{O}_{4}})}_{2}}\to 3C{{a}^{2+}}+2P{{O}_{4}}^{3-}\]$

The formula to find the number of moles is

Molarity$=\frac{Number of moles}{Volume of solution}$

Rearrange the equation,

Number of moles$\[=Molarity\times Volume\]$

$\[x=0.3\times 0.2\]$

$x=0.6$

Number of Moles of $\[C{{a}^{2+}}=0.6\]$$\[{{N}_{A}}\]$

Where $\[{{N}_{A}}\]$ is the Avogadro's constant

One mole contains exactly $\[6.02214076\times {{10}^{23}}\]$ elementary entities.