Question

the number of mole of nitrogen gas required to produce 10 mole of ammonia and presence of excess of hydrogen gas​

Answer 1

Answer:

5 moles

Explanation:

$N_{2} + 3H_{2} => 2NH_{3}$

1 mole of nitrogen gives 2 moles of ammonia

so ,

5 moles of nitrogen will give 10 moles of ammonia

Answer 2

Answer:

The number of moles of nitrogen gas required is 5 moles.

Explanation:

Assumption,

Let the number of moles of nitrogen gas required to produce 10 moles of ammonia and the presence of an excess hydrogen gas​ be 'x'.

Given,

The amount of ammonia produced is 10 moles.

To find,

The value of 'x'.

Calculation,

The reaction of nitrogen and hydrogen to get ammonia is as follows:
$N_2 + 3H_2 \rightarrow 2NH_3$

Now from above, we can conclude that 1 mole of nitrogen produces 2 moles of ammonia.

So, 10 moles of ammonia are produced when we take:
(1 × 10)/2 = 5 moles of nitrogen.

Therefore, the number of moles of nitrogen gas required is 5 moles.

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