The number of mole of nitrogen in one litre of air containing 10% nitrogen by volume, under standard conditions, is (1)0.03 moles (2)2.10moles (3)0.186moles (4)4.46 * 10 -3 mole
Answers
Answered by
552
The volume of nitrogen in the mixture is:
10% of the mixture = 10/100 x 1 liter
= 0.1 liters
Use ideal gas law to calculate the moles of the nitrogen gas.
Ideal gas law states that 1 mole of an ideal gas occupies 22.4 liters by volume.
Therefore, If 22.4 liters gives 1 mole,
then what will 0.1 mole give? = ( 0.1 x1/22.4) liters.
(use cross multiplication to come up with the answer)
= 0.1/22.4
= 4.46 x 10^-3
Hope you find this helpful.
10% of the mixture = 10/100 x 1 liter
= 0.1 liters
Use ideal gas law to calculate the moles of the nitrogen gas.
Ideal gas law states that 1 mole of an ideal gas occupies 22.4 liters by volume.
Therefore, If 22.4 liters gives 1 mole,
then what will 0.1 mole give? = ( 0.1 x1/22.4) liters.
(use cross multiplication to come up with the answer)
= 0.1/22.4
= 4.46 x 10^-3
Hope you find this helpful.
Answered by
60
Answer:
Volume percentage is defined as
Volume per cent = (volume of solute/ volume of solution)×100
Given the volume % is 10.
Let VN be the volume of N2 present in 1 litre of air.
Therefore we have,
10 = (VN/1)×100
VN = 10/100 = 0.1 litres of Nitrogen gas.
Now 22.4 litres of N2 gas = 1 mole of N2 gas.
Therefore 1 litre of N2 gas = 1/22.4 moles of N2 gas.
So 0.1 Litres of N2 gas = (1/22.4)×0.1 = 0.0045 moles.
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