the number of mole of nitrogen in one litre of air containing 10% nitrogen by volume under standard condition is
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at STP 22.4 litre of nitrogen=1 mole
as the total volume of solution is= 1L
So for 10% nitrogen volume will be= 0.1L
as 22.4L=1mole
1L= 1/22.4 mole
therefore, in 0.1L= (1/22.4)x0.1=0.0044 mole.
Explanation:
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