Question

The number of mole(s) of k2cr2o7 required to oxidise two moles of ferrous oxalate in acidic medium is

Answer 1

Hey Dear,

◆ Answer -

1 mole of K2Cr2O7

◆ Explanation -

Fe2+ in ferrous oxalate is oxidised to Fe3+ by acidified K2Cr2O7.

The reaction takes place as follows -

K2Cr2O7 + 7H2SO4 + 2FeC2O4 → Fe2(SO4)3 + K2SO4 + Cr2(SO4)3 + 4CO2 + 7H2O

That is, each mole of K2Cr2O7 oxidises 2 moles of ferrous sulphate.

Hence, to oxidize 2 moles of FeSO4, only 1 mole of K2Cr2O7 is required.

Hope this helps you.