Question

the number of molecules and no of atoms persent in 0.001 mol of phosphorus molecule respectively are(atomic mass of P is 31u)​

Answer 1

Answer: The given amount of phosphorus contains $6.022\times 10^{20}$ number of molecules and $2.41\times 10^{21}$ number of atoms.

Explanation:

A phosphorus molecule has a chemical formula $P_4$

We are given:

Moles of phosphorus molecule = 0.001 mole

In 1 mole of phosphorus molecule, 4 atoms of phosphorus is present.

According to mole concept:

1 mole of an element or compound contains $6.022\time 10^{23}$ number of atoms or molecules.

So, 0.001 moles of phosphorus will contain $0.001\times 6.022\times 10^{23}=6.022\times 10^{20}$ number of molecules and $4\times 0.001\times 6.022\times 10^{23}=2.41\times 10^{21}$ number of atoms.

Hence, the given amount of phosphorus contains $6.022\times 10^{20}$ number of molecules and $2.41\times 10^{21}$ number of atoms.

Answer 2

Answer:

Answer: The given amount of phosphorus contains 6.022\times 10^{20}6.022×10 ^20

number of molecules and 2.41\times 10^{21}2.41×10 ^

21 number of atoms.

Explanation:

A phosphorus molecule has a chemical formula P_4P

4

We are given:

Moles of phosphorus molecule = 0.001 mole

In 1 mole of phosphorus molecule, 4 atoms of phosphorus is present.

According to mole concept:

1 mole of an element or compound contains 6.022\time 10^{23}6.022\time10 ^23 number of atoms or molecules.

So, 0.001 moles of phosphorus will contain 0.001\times 6.022\times 10^{23}=6.022\times 10^{20}0.001×6.022×10 ^23

=6.022×10 ^20

number of molecules and 4\times 0.001\times 6.022\times 10^{23}=2.41\times 10^{21}4×0.001×6.022×10

23

=2.41×10 ^21 number of atoms.

Hence, the given amount of phosphorus contains 6.022\times 10^{20}6.022×10 ^20

number of molecules and 2.41\times 10^{21}2.41×10 ^

21 number of atoms.

Hope this helps you friend ;)