the number of molecules in 22.4cm^3 of nitrogen gas at stp is..... (a)6.022×10^20 (b)6.022×10^23 (c)22.4×10^20 (d)22.4×10^23
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Answer:
b according To Avagadro law
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1
Answer:
Explanation: 22.4cm^3 contain 22.4 × 0.001L
Mole = 22.4 × 0.001 / 22.4
= 0.001
No of molecule= 6.022 ×10^23 × 0.001
= 6.022 ×10^20
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