Question

The number of molecules in 4.25 g of NH, is
approximately
(1) 4 x 1023 (2) 1.5 x 1023
(3) 1 x 1023
(4) 6 x 1023​

Answer 1

Answer:

Explanation:

No.of Moles=Given Mass / Molar Mass.

Given Mass =4.25 g =17/4.

gMolar Mass of NH3 = 17g.

So No.of Moles =17/4 ÷ 17= ¼.

Therefore, No.of atoms=No.of Moles×6.022×10^23×Atomicity.

Atomicity of NH3 is 4i.e. No.of atoms=¼ × 6.022×10^23 × 4 = 6.022×10^23.....

Hence, the correct option is 4....

Answer 2

2

Explanation:

at first we divide 4.25 gm by the molar mass of NH then no of moles is obtained and we multiply it with 6*10^23