Question

The number of molecules of ethanol present in 92 g of ethanol is

(a) 6.022 x 1023 (b) 12.044 x 1023 (c) 18.066 x 1023 (d) 24.088 x 1023

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Answer 1

Answer:

12.044 x 10²³

Explanation:

Mass of ethanol = 92g

Chemical formula of ethanol = C₂H₅OH = C₂H₆O

Molar mass = 12x2 + 1x6+ 16 =24+6+16 = 46

No. of moles = $\frac{Mass}{Molar mass}$

                    = $\frac{92}{46}$

                    = 2 moles

No. of molecules = no. of moles x avogadro no.

                           = 2 x 6.022 x 10²³

                           = 12.044 x 10²³

Answer 2

Answer:

=12.044×10^23

Explanation:

ethanol=$C_{2} H_{5}OH$

molecular mass of ethanol=2×C+6×H+1×O

                                             =2×12+6×1+16×1

                                             =24+6+16=46 gram

46 gram of ethanol has=6.022×10^23

92 gram of ethanol has=6.022×10^23 × 2

                                       =12.044×10^23