The number of molecules of oxygen in 1L of air 21% of oxygen by volume at STP would be
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Answer:
55.8 x1020
Explanation:
21 percent in one litre =210 ml
Moles = 210/22400 =9.3 X 10-3
Molecules=mole X 6.022x 10 23
9.3x 10-3x 6.022X10 23
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