The number of molecules present in 0.36 g of water is
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Answer:
No. of H2O molecules in 0.36 g of water = 12.04 x 10^21
Explanation:
Step:-1. Calculate the mole of 0.36g of water..
Formula : n = m/M [n - no. of moles] [m - given mass] [M - molar mass]
Step:-2. We know that, molar mass(M) = 18g
So, no. of moles(n) = m/M = 0.36/18 = 0.02 mol...
Step:-3. n = N/Na [N - no. of molecules] [Na - Avogadro's no.]
Now, n = N/Na
=> 0.02 = N / 6.02 x 10^23
=> N = 0.02 x 6.02 x 10^23
=> N = 12.04 x 10^21 ....
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