Question

The number of molecules present in 0.36 g of water is

Answer 1

Answer:

No. of H2O molecules in 0.36 g of water = 12.04 x 10^21

Explanation:

Step:-1. Calculate the mole of 0.36g of water..

Formula : n = m/M [n - no. of moles] [m - given mass] [M - molar mass]

Step:-2. We know that, molar mass(M) = 18g

So, no. of moles(n) = m/M = 0.36/18 = 0.02 mol...

Step:-3. n = N/Na [N - no. of molecules] [Na - Avogadro's no.]

Now, n = N/Na

=> 0.02 = N / 6.02 x 10^23

=> N = 0.02 x 6.02 x 10^23

=> N = 12.04 x 10^21 ....