The number of molecules present in 0.44 g of CO2 gas is
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mole = given mass/ molar mass
so O has molar mass 16 and C has molar mass 12 MOL MASS OF CO2 is 44
mole=0.44/44= 1/100=0.01
no. of molecules= mole×avogadro no.
= 0.01×6.02×10^23=6.02×10^21 molecules
so O has molar mass 16 and C has molar mass 12 MOL MASS OF CO2 is 44
mole=0.44/44= 1/100=0.01
no. of molecules= mole×avogadro no.
= 0.01×6.02×10^23=6.02×10^21 molecules
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