the number of molecules present in 10 grams of aLCL 3 Answer all questions which are in the page
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given :-
mass =10
molecular weight of alcl3
alcl3=27+(35.5×3)=133.3
no of moles =weight /molecular weight
no of moles =10/133.3
no of moles =0.07
1mole =6.02×10^23
0.07 moles will have 0.07×6.02×10^23=0.42×10^23
given :-
mass =10
molecular weight of alcl3
alcl3=27+(35.5×3)=133.3
no of moles =weight /molecular weight
no of moles =10/133.3
no of moles =0.07
1mole =6.02×10^23
0.07 moles will have 0.07×6.02×10^23=0.42×10^23
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