Question

The number of molecules present in 10g of calcium carbonate is

Answer 1

number of molecules = given mass / molecular mass × avogadro number

molecular mass →

Ca = 40

C  =  12

O₃ = 48

total=80 g

using above formula,

no. of molecules = 10/80 × 6.022 × 10²³

                         = 7.52 × 10²¹