Question

The number of molècules present in 3.2g of oxygen is
1) 6x10^23
2) 1.2x10^23
3 ) 6x10^24​

Answer 1

Answer:

2) 1.2 x 10^23

Exp:

We know that,

Mass of Oxygen = 16g, and

16g of oxygen = 1 mole = 6.022 x 10^23 molecules.

Therefore, 1g = 6.022 x 10^23/16 molecules

Thus, 3.2g = 6.022 x 10^23/16 x 3.2

= 1.2044 x 10^23 molecules.

HOPE IT HELPS!!