the number of molecules present in 32 grams of oxygen
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NA no.of molecules
na= avg.no =6.02×10^23
na= avg.no =6.02×10^23
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n = m ÷ M ( given mass ÷ molar mass )
therefore ( given mass = 32 gm and molar mass = 16 ) hence n = 32÷16 = 2
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therefore ( given mass = 32 gm and molar mass = 16 ) hence n = 32÷16 = 2
made it is helpful for you thanks
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