Chemistry, asked by prinku918, 1 year ago

The number of molecules present in 56ml of CO2 at STP

Answers

Answered by gurleenkaur21
27
molar mass of gas at STP = 22.4 litres
1 litre = 1000 ml
22.4 litre = 22.4 × 1000 = 22400 ml
molar mass of co2 at STP = 44×22400 gm
no. of moles = 56÷ 44 × 22400
= 0.11 moles
no. of molecules = moles × avogadro no.
= 0.11 × 6.022 × 10 raised to the power 23
= 66.242 × 10 raised to the power 21 molecules
hopefully it is the answer
Answered by kobenhavn
13

Answer: 15.06\times 10^{20} molecules of CO_2

Explanation:

According to Avogadro's law, 1 mole of every substance occupy 22.4 L at STP and contains avogadro's number (6.023\times 10^{23}) of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given volume}}{\text{Molar volume}}  

Putting values in above equation, we get:

\text{Moles of gold}=\frac{56ml}{2240ml}=2.5\times 10^{-3}moles

Thus 2.5\times 10^{-3}moles   of CO_2 will contain=\frac{6.023\times 10^{23}}{1}\times 2.5\times 10^{-3}=15.06\times 10^{20} molecules of CO_2

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