Question

The number of molecules present in 88 g of CO2 (Relative molecular mass of CO2 = 44)
(A) 1.24 x 10%
(B) 3.01 x 1023
(C) 6.023 x 1024 (D) 1.2046 *10^24
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Answer 1

no of moles= 88/44 =2

therefore no. of molecules =

6.023 \times {10}^{23} \times 26.023×10

23

×2

therefore no.of molecules= 12.046*10^23

so Option D is Answer

Answer 2

Answer:

option d

Explanation:

photo is attached plz refer from detailed solution