Question

the number of moles of cacl2 needed to react with excess of AG and O3 to produce 4.31 gram of agcl is

Answer 1

Calculate the number of grams of calcium chloride (CaCl2) needed to react with excess silver nitrate (AgNO3) to produce 6.60 g of silver chloride (AgCl). The equation for the reaction is given below:

CaCl2 + 2AgNO3 → 2AgCl + Ca(NO3)2

Steve Monday, November 5, 2012 at 1:14pm

6.6g AgCl = .046 moles

each mole CaCl2 yields 2 moles AgCl, so only 0.023 moles CaCl2 are needed.

.023 moles CaCl2 = 2.55g please mark as brainlies im trying to level up