Question

The number of moles of electron required to reduce 0.2 mole of Cr2o7-² to Cr+³ is?
with explaination .
shortcut method if it is there.​

Answer 1

◆ Answer -

1.2 moles e⁻

◆ Explanation -

Cr2O7²⁻ is reduced to Cr3+ according to following reaction -

Cr2O7²⁻ + 14H+ + 6e- → 2Cr3+ + 8H2O

That is 6 e- are required to reduce 1 mol of Cr2O7²⁻.

Electrons required to reduce 0.2 mol Cr2O7²⁻ are -

n' = 6 × 0.2

n' = 1.2 mol e-

Hence, 1.2 moles of electron required to reduce 0.2 mol of Cr2O7²⁻.

Hope you understand..!!!

Read more on Brainly.in - https://brainly.in/question/9609079#readmore

Explanation: