Question

The number of moles of hydroxide (OH) ions in 0.3 liter of 0.0005 M solution of Ba(OH), is​

Answer 1

Answer:

0.3L = 0.3L of 0.0005 M Na(oh)2

0.3*0.0005= 0.0015 moles of Ba(OH)

it will dissociate into Ba and

2*0.0015= 0.003 moles of OH ions

Answer 2

Explanation:

Molarity is no of moles of solute/volume of aol in litres

So no of moles of solute is 0.005*0.3=0.0015

As in the solute we have 2OH we hav to multiply 2 with 0.0015 and that gives 0.0030