Question

The number of moles of iron in a mixture of 112gms FEO and 320 grams of Fe2O3 will be​

Answer 1

Answer:

Explanation:

Mole= 112÷56=2moles

Mole=320÷160=2moles

Answer 2

Answer:

The total number of moles of iron present in a mixture of 112gms FeO and 320 grams of Fe₂O₃ is 5.55

Explanation:

Given,

The weight of FeO (W) is 112 gm.

The weight of Fe₂O₃ (w) is 320 gm.

To find,

The total number of moles of iron(Fe) in the mixture of 112 gm of FeO, and 320 gm of Fe₂O₃.

Calculation,

The number of moles of Fe from FeO:

1 mole of FeO contains 1 mole of Fe then, the number of moles of Fe in 112 gm of FeO is:

n1 = weight of FeO/ G.M.W of FeO

⇒ n1 = 112/72

⇒ n1 = 1.55 moles

The number of moles of Fe from Fe₂O₃:

1 mole of Fe₂O₃ contains 2 moles of Fe then, the number of moles of Fe in 320 gm of Fe₂O₃ is :

$n2 = 2 \times \frac{weight \ of \ F_2O_3}{G.M.W \ of Fe_2O_3}$

$\implies n2 = 2 \times \frac{320}{160}$

⇒ n2 = 2 × 2

⇒ n2 = 4 moles

Hence, the total number of moles of Fe is n1 + n2 = 1.55 + 4 = 5.55 moles

Therefore, the total number of moles of iron present in a mixture of 112gms FeO and 320 grams of Fe₂O₃ is 5.55

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