The number of moles of KMnO4 reduced by one mole of KI in alkaline medium is:
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Answer:
Thus 2 moles of KMnO4 reduced by one mole of KI in alkaline medium.....
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Answer:
KI+2KMnO4+H2O —->KIO3+2KOH+MnO2
Hence 2 moles of KMnO4 will be will be reduced by one mole of KI in alkaline medium.
Explanation:
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