Question

The number of moles of lead nitrate needed to coagulate 2 mol of colloidal [agi]i[agi]i is :

Answer 1

Answer: 1

2[AgI]I−+Pb2+⟶PbI2+2AgI

Thus, 2 moles of [AgI]I− are coagulated by 1 mole of Pb2+ i.e., 1 mole of Pb(NO3)2

Answer 2

Answer:

For Coagulation only one mole of lead nitrate Pb(NO₃)₂ needs to coagulate 2mol of colloidal of [AgI]I⁻.

Explanation:

• Coagulation in which the colloidal particles do not form colloidal solution instead of that  aggregates together and in form precipitates settle down on the bottom of vessel.
• Factors affect Coagulation: particle size, temperature, change in pH, density.

In the given coagulation:

                $2[AgI]I^{-}+Pb^{2+}$   →   $PbI_{2}+2AgI$

Therefore 1 mole of lead nitrate coagulates with 2moles of  [AgI]I⁻.