The number of moles of NaCl in 3 litres of 3M solution is
(a) 1
(b) 3
(c) 9
(d) 27
Answers
Answer- The above question is from the chapter 'Some Basic Concepts of Chemistry'.
Molarity: Number of moles of solute present in 1 litre of solution is called molarity.
Unit of Molarity = Molar (M)
•When volume is given in litres,
Molarity = Number of moles of solute ÷ Volume of solution in litres
•When volume is given in millilitres
Molarity = (Number of moles of solute × 1000) ÷ Volume of solution in ml
•When mass % and density is given,
Molarity = (Mass % × Density × 10) ÷ Molar mass of Solute
Given question: The number of moles of NaCl in 3 litres of 3 M solution is
(a) 1
(b) 3
(c) 9
(d) 27
Answer: Molarity = Number of moles of solute ÷ Volume of solution in litres
3 M = Number of moles ÷ 3 L
3 × 3 = Number of moles
∴ Number of moles of NaCl = 9
Or
3 M means 3 moles in 1 litre of solution.
⇒ Number of moles in 3 litres solution = 3 × 3 = 9 moles
∴ Number of moles of NaCl = 9
(c) 9 is the correct answer.
Answer:
Molarity is equal to the number of moles of solute divided by the volume of solution in litres.
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